document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=869200>Question 869200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You have a square and a rectangle and are told their combined area is 67.  You are told the rectangle has a width of 3 cm more than the length of a side of the square and the rectangle has a width 2 cm more than the length of a side of the square.  Find the dimensions of the rectangle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #524094 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=524094\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the side of the square equal s.<BR>\n" );
document.write( "s^2+(s+3)(s+2)=67<BR>\n" );
document.write( "s^2+s^2+5s+6=67<BR>\n" );
document.write( "2s^2+5s-61=0<BR>\n" );
document.write( "s=(3sqrt(57)-5)/4) Quadratic formula<BR>\n" );
document.write( "(s+3)(s+2)<BR>\n" );
document.write( "=(((3sqrt(57)-5)/4)+3)cm. and (((3sqrt(57)-5)/4)+2) cm. The dimensions of the rectangle.<BR>\n" );
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