document.write( "Question 73131This question is from textbook
\n" ); document.write( ": Mr. Sable invested $5000 in a mortgage that pays 9% interest annually. He bought bonds paying 4.5% interest annually. His total annual income is 6% of his total investment. How much did he invest in the bonds. \n" ); document.write( "

Algebra.Com's Answer #52402 by Earlsdon(6294) $\"\"$ $\"About$

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Probably, the trickiest part of solving word problems is setting up the equation that correctly reflects the given situation.
\n" ); document.write( "Let B equal the amount Mr. Sable invested in bonds.
\n" ); document.write( "The amount of interest earned by the mortgage investment can be written, after changing the percentage to its decimal equivalent:
\n" ); document.write( " $\"5000%280.09%29\"$
\n" ); document.write( "The amount of interest eaned by the bonds investment can be written:
\n" ); document.write( " $\"B%280.045%29\"$
\n" ); document.write( "The total annual income can be written:
\n" ); document.write( " $\"%285000%2BB%29%280.06%29\"$ Put it all together and you get:
\n" ); document.write( " $\"5000%280.09%29%2BB%280.045%29+=+%285000%2BB%29%280.06%29\"$ Simplify and solve for B.
\n" ); document.write( " $\"450%2B0.045B+=+300%2B0.06B\"$ Subtract 300 from both sides.
\n" ); document.write( " $\"150%2B0.045B+=+0.06B\"$ Subtract 0.045B from both sides.
\n" ); document.write( " $\"150+=+0.015B\"$ Divide both sides by 0.015
\n" ); document.write( " $\"10000+=+B\"$
\n" ); document.write( "Mr. Sable invested $10,000.00 in bonds.
\n" ); document.write( "Check:
\n" ); document.write( " $\"5000%280.09%29%2B10000%280.045%29+=+450%2B450\"$ = $900.00 Total earned interest.
\n" ); document.write( " $\"%285000%2B10000%29%280.06%29+=+15000%280.06%29\"$ = $900.00 Toatal earned interest. \n" ); document.write( "

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