document.write( "Question 9674: How do you find the length and width of a rectangle if the perimeter=38 and the area=90 square meters? \n" ); document.write( "
Algebra.Com's Answer #5240 by Earlsdon(6294)\"\" \"About 
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You could try this:\r
\n" ); document.write( "\n" ); document.write( "A = L X W = 90 m^2 This is the area.\r
\n" ); document.write( "\n" ); document.write( "P = 2(L+W) = 38 m This is the perimeter. Solve this for L and substitute in the above equation, then solve for W.\r
\n" ); document.write( "\n" ); document.write( "2(L+W) = 38
\n" ); document.write( "L+W = 19
\n" ); document.write( "L = 19-W\r
\n" ); document.write( "\n" ); document.write( "\"%2819-W%29W+=+90\" Simplify and solve for W
\n" ); document.write( "\"19W+-+W%5E2+=+90\"
\n" ); document.write( "\"W%5E2+-+19W+%2B+90+=+0\" Solve this quadratic by factoring.
\n" ); document.write( "\"%28W-9%29%28W-10%29=+0\" Apply the zero product principle.\r
\n" ); document.write( "\n" ); document.write( "W-9 = 0 or W-10 = 0\r
\n" ); document.write( "\n" ); document.write( "If W-9 = 0, then w = 9
\n" ); document.write( "If W-10 = 0, then W = 10\r
\n" ); document.write( "\n" ); document.write( "These two numbers are actually the length and the width of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "L = 10 m and W = 9 m.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "A = LW = 10(9) = 90 m^2
\n" ); document.write( "P = 2(L+W) = 2(10+9) = 2(19) = 38 meters.
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