document.write( "Question 9674: How do you find the length and width of a rectangle if the perimeter=38 and the area=90 square meters? \n" ); document.write( "
Algebra.Com's Answer #5240 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! You could try this:\r \n" ); document.write( "\n" ); document.write( "A = L X W = 90 m^2 This is the area.\r \n" ); document.write( "\n" ); document.write( "P = 2(L+W) = 38 m This is the perimeter. Solve this for L and substitute in the above equation, then solve for W.\r \n" ); document.write( "\n" ); document.write( "2(L+W) = 38 \n" ); document.write( "L+W = 19 \n" ); document.write( "L = 19-W\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "W-9 = 0 or W-10 = 0\r \n" ); document.write( "\n" ); document.write( "If W-9 = 0, then w = 9 \n" ); document.write( "If W-10 = 0, then W = 10\r \n" ); document.write( "\n" ); document.write( "These two numbers are actually the length and the width of the rectangle.\r \n" ); document.write( "\n" ); document.write( "L = 10 m and W = 9 m.\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "A = LW = 10(9) = 90 m^2 \n" ); document.write( "P = 2(L+W) = 2(10+9) = 2(19) = 38 meters. \n" ); document.write( " |