document.write( "Question 869023: The pair of points is on the graph of an inverse variation. Find the missing value.\r
\n" ); document.write( "\n" ); document.write( "(9, 5) and (x, 6)
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Algebra.Com's Answer #523986 by Theo(13342)\"\" \"About 
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your points are (9,5) and (x,6)\r
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\n" ); document.write( "\n" ); document.write( "inverse variation equation is:\r
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\n" ); document.write( "\n" ); document.write( "y = k/x\r
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\n" ); document.write( "\n" ); document.write( "when x - 5 and y = 9, this equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "5 = k/9
\n" ); document.write( "multiply both sides of this equation by 9 to get:
\n" ); document.write( "k = 9*5 = 45\r
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\n" ); document.write( "\n" ); document.write( "now you can use the value of k to solve for x in the second pair of (x,6)\r
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\n" ); document.write( "\n" ); document.write( "your equation is still y = k/x
\n" ); document.write( "now you have y = 6 and k = 45.
\n" ); document.write( "use those values to get:\r
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\n" ); document.write( "\n" ); document.write( "6 = 45 / x
\n" ); document.write( "multiply both sides of this equation by x to get:
\n" ); document.write( "6*x = 45
\n" ); document.write( "divide both sides of this equation by 6 to get:
\n" ); document.write( "x = 45/6 which is equal to 7.5\r
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\n" ); document.write( "\n" ); document.write( "your answer is that x = 7.5\r
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