document.write( "Question 868986: Please mail me this answer..asap
\n" ); document.write( "Train A is heading north to south at a speed of 40 miles per hour. Train B is heading south to
\n" ); document.write( "north at a speed of 50 miles per hour. A and B are traveling toward each other on
\n" ); document.write( "neighboring tracks and the distance between them is 180 miles and there are no stations
\n" ); document.write( "between them. A bird is flying back and forth between them at a speed of 55 miles per hour.
\n" ); document.write( "The bird will keep flying until the trains cross each other. What is the distance traveled by the bird before the crossing happens?
\n" ); document.write( "a) 180 miles
\n" ); document.write( "b) 110 miles
\n" ); document.write( "c) 135 miles
\n" ); document.write( "d) 90+ 90/2+90/4+90/6….. miles \r
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Algebra.Com's Answer #523977 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Train A is heading north to south...
\n" ); document.write( "That's heading south.
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\n" ); document.write( "Going in opposite directions, the speeds are added, often called the \"closing speed.\"
\n" ); document.write( "40 + 50 = 90 mi/hr
\n" ); document.write( "d = r*t
\n" ); document.write( "t = d/r = 2 hours until they meet
\n" ); document.write( "------
\n" ); document.write( "The bird flies for 2 hours at 55 mi/hr
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