document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=868882>Question 868882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE HELP. A CUBE OF ICE 3 FT BY 3 FT BY 3 FT. THE ICE MELTS UNTIL IT BECOMES A CUBE WHICH IS ONE HALF AS HEAVY AS THE ORIGINAL. FIND THE DIMENSION OF A NEW CUBE (DENSITY OF ICE=62LB/CUB.FT. THANK YOU </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #523960 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=523960\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> volume of cube = 3 * 3 * 3 = 27 cubic feet<BR>\n" );
document.write( "ice weighs 57.4 pounds per cubic foot, therefore<BR>\n" );
document.write( "our cube of ice weighs 57.4 * 27 = 1549.8 pounds<BR>\n" );
document.write( "now 1/2 of that is 1549.8 / 2 = 774.9 pounds<BR>\n" );
document.write( "x^3 * 57.4 = 774.9<BR>\n" );
document.write( "x^3 = 774.9 / 57.4 = 13.5<BR>\n" );
document.write( "x = 13.5 ^ (1/3) = 2.38 feet\r<BR>\n" );
document.write( "\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );