document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=868957>Question 868957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a random sample of 75 shoppers at a grocery store ,20 were found to spend in excess of 30 minutes shopping. Assuming the times are approximately normally distributed, determine the maximum error of estimate for the proportion of the population with 80% confidence. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #523939 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=523939\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a random sample of 75 shoppers at a grocery store ,20 were found to spend in excess of 30 minutes shopping. Assuming the times are approximately normally distributed, determine the maximum error of estimate for the proportion of the population with 80% confidence.<BR>\n" );
document.write( "----<BR>\n" );
document.write( "ME = z*sqrt[pq/n]<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "ME = 1.2816*sqrt[(20/75)((55/75)/75] = 0.0654<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );