document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73141>Question 73141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many kg of water must be evaporated from 50kg of a 10% salt solution to obtain a 15% salt solution?\r<BR>\n" );
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document.write( "This was given to me out of a GEPA math tutorial book. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52392 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52392\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many kg of water must be evaporated from 50kg of a 10% salt solution to obtain a 15% salt solution?<BR>\n" );
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document.write( "Amt of water in 10% solution = 0.90*50kg = 45kg<BR>\n" );
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document.write( "Let amt of water evaporated be \"x\" kg.<BR>\n" );
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document.write( "Amt of water in 15% solution = 0.85(50-x)=(42.5-0.85x)kg<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "water - water = water<BR>\n" );
document.write( "45 - x= 42.5-0.85x<BR>\n" );
document.write( "2.5=0.15x<BR>\n" );
document.write( "x= 6 2/3 kg (amt of water that must be evaporated)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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