document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=868941>Question 868941</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters of 30% silver must be added to 80 liters of 50% silver to make an alloy that is 40% silver? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #523916 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=523916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many liters of 30% silver must be added to 80 liters of 50% silver to make an alloy that is 40% silver?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "silver + silver = silver<BR>\n" );
document.write( "0.30x + 0.50*80 = 0.40(x+80)<BR>\n" );
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document.write( "30x + 50*80 = 40x + 40*80<BR>\n" );
document.write( "10x = 10*80<BR>\n" );
document.write( "x = 80 liters (amt. of 30% alloy to add)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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