document.write( "Question 868930: If 10% of television sets produced by Hybrid Electrics have some form of defect, determine the probability that out of five (5) television sets chosen at random\r
\n" ); document.write( "\n" ); document.write( "(a) Only one will be defective. P(X=1)………………………………… [2]
\n" ); document.write( "(b) At most two will be defective. P (X ≤ 2) =…………………………… [2]
\n" ); document.write( "(c) More than three will be defective. P(X>3) =……………………………
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Algebra.Com's Answer #523903 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
\n" ); document.write( "p(def) = .10, n = 5
\n" ); document.write( "P(X=1) = binompdf(5, .10, 1)= .3281
\n" ); document.write( "P (X ≤ 2)= binomcdf(5, .10,2)= .9914
\n" ); document.write( "P(X>3) = 1 - binomcdf(5, .10,3)= .0005 \n" ); document.write( "
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