document.write( "Question 868822: 5^x=1258\r
\n" ); document.write( "\n" ); document.write( "set up the change of base rule, solve for x. \n" ); document.write( "

Algebra.Com's Answer #523851 by josgarithmetic(39620) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"1258=2%2A17%2A37\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"log%285%2C1258%29=x\"$
\n" ); document.write( " $\"x=log%2810%2C1258%29%2Flog%2810%2C5%29\"$ , applying Change of Base formula\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"x=3.09968%2F0.69897\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"x=4.435\"$
\n" ); document.write( " \n" ); document.write( "

\n" );