document.write( "Question 868804: Write a system of two equations in two variables to solve the problem.\r
\n" ); document.write( "\n" ); document.write( "Flying with a tailwind, a pilot flew an airplane 720 miles in 4.5 hours. Flying into a headwind, the return trip took 6 hours. Find the speed of the plane in calm air and the speed of the wind.
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Algebra.Com's Answer #523835 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Plane speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 6 hours
\n" ); document.write( "with wind 4.5 hours
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\n" ); document.write( "Distance against 720 miles distance with 720 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "720.00 / ( x - y )= 6.00
\n" ); document.write( "6.00 ( x - y ) = 4.50
\n" ); document.write( "6.00 x - 6.00 y = 720.00 ....................1
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\n" ); document.write( "720.00 / ( x + y )= 4.50
\n" ); document.write( "4.50 ( x + y ) = 720.00
\n" ); document.write( "4.50 x + 4.50 y = 720.00 ...............2
\n" ); document.write( "Multiply (1) by 4.50
\n" ); document.write( "Multiply (2) by 6.00
\n" ); document.write( "we get
\n" ); document.write( "27.00 x + -27.00 y = 3240.00
\n" ); document.write( "27.00 x + 27.00 y = 4320.00
\n" ); document.write( "54.00 x = 7560.00
\n" ); document.write( "/ 54.00
\n" ); document.write( "x = 140.00 mph
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\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "6.00 x -6.00 y = 720.00
\n" ); document.write( "840.00 -6.00 -840.00 = 720.00
\n" ); document.write( "-6.00 y = 720.00
\n" ); document.write( "-6.00 y = -120.00 mph
\n" ); document.write( " y = 20.00
\n" ); document.write( "Plane speed 140.00 mph
\n" ); document.write( "wind speed 20.00 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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