document.write( "Question 73136: $1000 was invested altogether. The first investment yielded a 15% profit, but the second investment yielded a 10% loss. Altogether this was equivalent to a 6% loss. How much in each investment? \n" ); document.write( "
| Algebra.Com's Answer #52382 by stanbon(75887)      You can put this solution on YOUR website! $1000 was invested altogether. The first investment yielded a 15% profit, but the second investment yielded a 10% loss. Altogether this was equivalent to a 6% loss. How much in each investment? \n" ); document.write( "------------- \n" ); document.write( "Let amt of 15% investment be \"x\" ; Interest will be 0.15x \n" ); document.write( "Amt of 10% investment is \"1000-x\": Interest will be 0.10(1000-x)=100-0.1x \n" ); document.write( "--------------- \n" ); document.write( "EQUATION: \n" ); document.write( "Int - Int = -0.06(1000) \n" ); document.write( "0.15x - (100-0.10x) = -0.06(1000) \n" ); document.write( "0.15x-100+0.10x = -60 \n" ); document.write( "0.05x=40 \n" ); document.write( "x=$800 (amt invested at 15%) \n" ); document.write( "1000-x = $200 (amt invested at 10%) \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |