document.write( "Question 868730: To qualify for security officers’ training, recruits are tested for stress tolerance. The recruits in the top 38.7% qualify for advanced training. The scores are found to be normally distributed with a mean of 88 and standard deviation of 6.2 (these are not percent scores). Determine the lowest whole number score for an applicant who qualifies for advanced training. \n" ); document.write( "
Algebra.Com's Answer #523780 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! z = invNorm(.613) = .2871 \n" ); document.write( ".2871*6.2 + 88 = X (rounded UP, the lowest score) \n" ); document.write( " \n" ); document.write( " |