document.write( "Question 868535: Question: solve the equation in the interval [0,2pi)
\n" ); document.write( "tan³(x) + tan²(x) - 3tan(x) - 3 = 0 \n" ); document.write( "

Algebra.Com's Answer #523760 by Edwin McCravy(20054) $\"\"$ $\"About$

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document.write( "tan³(x) + tan²(x) - 3tan(x) - 3 = 0\r\n" );
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document.write( "Factor by grouping.  \r\n" );
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document.write( "Factor tan²(x) out of the\r\n" );
document.write( "first two terms on the left.\r\n" );
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document.write( "Factor -3 out of the\r\n" );
document.write( "last two terms on the left.\r\n" );
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document.write( "tan²(x)[tan(x) + 1] - 3[tan(x) + 1] = 0\r\n" );
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document.write( "Factor [tan(x) + 1] out of both terms on the left:\r\n" );
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document.write( "[tan(x) + 1][tan²(x) - 3] = 0\r\n" );
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document.write( "Use the zero-factor property:\r\n" );
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document.write( "tan(x) + 1 = 0;   tan²(x) - 3 = 0\r\n" );
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document.write( "    tan(x) = -1       tan²(x) = 3\r\n" );
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document.write( " x = ,             tan = ±√3\r\n" );
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document.write( "                      x = ,, , \r\n" );
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document.write( "Edwin

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