document.write( "Question 868663: Sove for x when [0,2pi) [sin(2x) sin(x)]/2=cosx \n" ); document.write( "
Algebra.Com's Answer #523751 by lwsshak3(11628)\"\" \"About 
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Sove for x when [0,2pi) [sin(2x) sin(x)]/2=cosx
\n" ); document.write( "\"2%28sin%28x%29cos%28x%29%2Asin%28x%29%29=2cos%28x%29\"
\n" ); document.write( "cancel out 2cos(x)
\n" ); document.write( "sin^2(x)=1
\n" ); document.write( "sin(x)=±1
\n" ); document.write( "x=π/2, 3π/2\r
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