document.write( "Question 868686: Please help me solve this problem.\r
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document.write( "A person paddles 1 mi upstream and 1 mile down stream in a total of 1 hour. The speed of the river is 2mph. What is the speed of the persons boat in still water? \n" );
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Algebra.Com's Answer #523745 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Please help me solve this problem. \n" ); document.write( "A person paddles 1 mi upstream and 1 mile down stream in a total of 1 hour. The speed of the river is 2mph. What is the speed of the persons boat in still water? \n" ); document.write( "----------- \n" ); document.write( "Let \"b\" be the speed of the boat in still water. \n" ); document.write( "----- \n" ); document.write( "Upstream DATA: \n" ); document.write( "distance = 1 mile ; rate = b-2 mph ; time = d/r = 1/(b-2) hrs \n" ); document.write( "------------------------ \n" ); document.write( "Downstream DATA: \n" ); document.write( "distance = 1 mile ; rate = b+2 mph ; time = d/r = 1/(b+2) hrs \n" ); document.write( "------------------------ \n" ); document.write( "Equation: \n" ); document.write( "time + time = 1 hr. \n" ); document.write( "1/(b-2) + 1/(b+2) = 1 \n" ); document.write( "-------- \n" ); document.write( "b+2 + b-2 = b^2-4 \n" ); document.write( "--- \n" ); document.write( "2b = b^2-4 \n" ); document.write( "----- \n" ); document.write( "b^2-2b-4 = 0 \n" ); document.write( "------ \n" ); document.write( "Use the quadratic formula to get: \n" ); document.write( "b = [2 +- sqrt(4-4*-4)]/2 \n" ); document.write( "b = [2 +- sqrt(20)]/2 \n" ); document.write( "Positive solution:: \n" ); document.write( "b = [2+2sqrt(5)]/2 \n" ); document.write( "b = 1+sqrt(5) \n" ); document.write( "b = 3.24 mph (speed of the boat in stil water) \n" ); document.write( "-------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------------------ \n" ); document.write( " \n" ); document.write( " |