document.write( "Question 868686: Please help me solve this problem.\r
\n" ); document.write( "\n" ); document.write( "A person paddles 1 mi upstream and 1 mile down stream in a total of 1 hour. The speed of the river is 2mph. What is the speed of the persons boat in still water?
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Algebra.Com's Answer #523745 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Please help me solve this problem.
\n" ); document.write( "A person paddles 1 mi upstream and 1 mile down stream in a total of 1 hour. The speed of the river is 2mph. What is the speed of the persons boat in still water?
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\n" ); document.write( "Let \"b\" be the speed of the boat in still water.
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "distance = 1 mile ; rate = b-2 mph ; time = d/r = 1/(b-2) hrs
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\n" ); document.write( "Downstream DATA:
\n" ); document.write( "distance = 1 mile ; rate = b+2 mph ; time = d/r = 1/(b+2) hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "time + time = 1 hr.
\n" ); document.write( "1/(b-2) + 1/(b+2) = 1
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\n" ); document.write( "b+2 + b-2 = b^2-4
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\n" ); document.write( "2b = b^2-4
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\n" ); document.write( "b^2-2b-4 = 0
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\n" ); document.write( "Use the quadratic formula to get:
\n" ); document.write( "b = [2 +- sqrt(4-4*-4)]/2
\n" ); document.write( "b = [2 +- sqrt(20)]/2
\n" ); document.write( "Positive solution::
\n" ); document.write( "b = [2+2sqrt(5)]/2
\n" ); document.write( "b = 1+sqrt(5)
\n" ); document.write( "b = 3.24 mph (speed of the boat in stil water)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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