document.write( "Question 868555: how much pure acid should be mixed with 5 gallons of 40% acid in order to get a 50% acid solution? \n" ); document.write( "

Algebra.Com's Answer #523628 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( " x + .40(5gal) = .50(.40 +x)
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document.write( "     x = .10(5gal)/.5
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document.write( "recommend keeping the details intact and then use calculator (easy to check setUP) \n" );
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