document.write( "Question 868496: A wheel of fortune contains the integers 1 to 100, inclusive. Two people play against each other. One player wins if the wheel lands on a multiple of either 3 or 7, and the other player wins if it lands on a multiple of 4 or 6. If neither player wins, the house takes both bets. What's the probability that the house wins? \n" ); document.write( "
Algebra.Com's Answer #523615 by Fombitz(32388)\"\" \"About 
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There are \"33\" multiples of \"3\" from \"1\" to \"100\".
\n" ); document.write( "There are \"25\" multiples of \"4\" from \"1\" to \"100\".
\n" ); document.write( "There are \"16\" multiples of \"6\" from \"1\" to \"100\".
\n" ); document.write( "There are \"14\" multiples of \"7\" from \"1\" to \"100\".
\n" ); document.write( "That means \"33%2B25%2B16%2B14=88\" outcomes are wins for the players.
\n" ); document.write( "So 12 outcomes are wins for the house.
\n" ); document.write( "\"P%28House+win%29=12%2F100=3%2F25\"
\n" ); document.write( "If I was you, I'd choose 3 or 7.
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