document.write( "Question 868504: This question is ridiculously confusing to me, any help is greatly appreciated!\r
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document.write( "If it is known that sin a = 4/5, pi/2 < a < pi\r
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document.write( "and that sin b = - (2 * sqrt(5) / 5), pi < b < 3pi/2,\r
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document.write( "find the exact value of cos( a + b )\r
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document.write( "Pretty please help me out, i'm in a crunch right now :/ thanks though :) \n" );
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Algebra.Com's Answer #523592 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! From trig relation, \n" ); document.write( " \n" ); document.write( "So you need to find \n" ); document.write( "Since \n" ); document.write( "then, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Since you're given information that \n" ); document.write( " \n" ); document.write( "Now for \n" ); document.write( "Same thing, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "From the information, \n" ); document.write( " \n" ); document.write( "Now go back to the original equation and plug in the values. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "As a check using inverse trig functions, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |