document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=868430>Question 868430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line through (0,1) and perpendicular to the line 3x+4y=5. \r<BR>\n" );
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document.write( "choices: A. 4x-3y=5, B. 4x-3y=-3, C. 5x-3y=4, D. 3x+4y=-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #523554 by </B><A HREF=/tutors/aboutme.mpl?userid=JLJL><B>JLJL(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JLJL><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=523554\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the question, we know there are 2 different straight lines intersecting to each other in perpendicular manner.\r<BR>\n" );
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document.write( "From the given equation of the first straight line, 3x + 4y = 5, we can find its gradient by rearranging the equation in the form of Y = mX + C, the step is shown as below.<BR>\n" );
document.write( "3x + 4y = 5<BR>\n" );
document.write( "4y = -3x + 5<BR>\n" );
document.write( "y = -(3/4)x + (5/4)<BR>\n" );
document.write( "When comparing with Y = mX + C, where m is the gradient. We can know the value of the gradient of the first straight line, m1 = -(3/4)\r<BR>\n" );
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document.write( "When two lines are perpendicular to each other, the product of gradient of the two lines must be equal to -1. \r<BR>\n" );
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document.write( "We can now calculate the value of the gradient of the second straight line as below.<BR>\n" );
document.write( "m1 x m2 = -1<BR>\n" );
document.write( "(-3/4) x m2 = -1<BR>\n" );
document.write( "m2 = [(-1)x4]/[-3]<BR>\n" );
document.write( "m2 = 4/3\r<BR>\n" );
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document.write( "To find the equation of the second straight line at point (0, 1), use the formula, y2 - y1 = m(x2 - x1)<BR>\n" );
document.write( "y2 - 1 = (4/3)(x2 - 0)<BR>\n" );
document.write( "y2 = (4/3)x2 + 1<BR>\n" );
document.write( "3y2 = 4x2 + 3\r<BR>\n" );
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document.write( "Rearranging 3y = 4x + 3, we can get 4x - 3y = -3. Therefore, The answer is B.   </SPAN>\n" );
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