document.write( "Question 868424: domain of y= sqrt(x-1)+sqrt(6-x) \n" ); document.write( "
Algebra.Com's Answer #523533 by jim_thompson5910(35256)\"\" \"About 
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You cannot have a negative in the square root. So the radicands must be 0 or positive.\r
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\n" ); document.write( "\n" ); document.write( "That means,\r
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\n" ); document.write( "\n" ); document.write( "\"x-1%3E=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-1%2B1%3E=0%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=1\"\r
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\n" ); document.write( "\n" ); document.write( "AND it also means\r
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\n" ); document.write( "\n" ); document.write( "\"6-x%3E=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"6-x%2Bx%3E=0%2Bx\"\r
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\n" ); document.write( "\n" ); document.write( "\"6%3E=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=6\"\r
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\n" ); document.write( "\n" ); document.write( "We found that \"x%3E=1\" AND \"x%3C=6\"\r
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\n" ); document.write( "\n" ); document.write( "So put together, the restrictions on x are \"1%3C=x%3C=6\" (basically, x is between 1 and 6 including both endpoints)\r
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\n" ); document.write( "\n" ); document.write( "The domain is the set of x values such that \"1%3C=x%3C=6\"\r
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\n" ); document.write( "\n" ); document.write( "In interval notation, the domain is [1,6]
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