document.write( "Question 868331: The side of the triangle are 20m, 25m , and 30m repectively. Find the Length of the altitude to the longest side? \n" ); document.write( "
Algebra.Com's Answer #523531 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Use Law of Cosines...\r
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\n" ); document.write( "\n" ); document.write( "A picture will help but is not here included.\r
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\n" ); document.write( "\n" ); document.write( "Pick the interior angle at the vertex of the 20 m and 30 m sides. Call the angle measure, t.
\n" ); document.write( "\"20%5E2%2B30%5E2-2%2A20%2A30%2Acos%28t%29=25%5E2\"
\n" ); document.write( ".
\n" ); document.write( "\"1300-625=1200cos%28t%29\"
\n" ); document.write( "\"cos%28t%29=675%2F1200\"
\n" ); document.write( "\"cos%28t%29=9%2F16\"
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\n" ); document.write( "What is this value of t?
\n" ); document.write( "\"arcos%289%2F16%29=55.7711\" degrees for more accuracy than needed.\r
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\n" ); document.write( "\n" ); document.write( "Use the 20 meter length side as the hypotenuse of a right triangle which contains the altitude and part of the base side; we do not need the base side nor part of it here. We only want to compute the altitude. This altitude is:\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28highlight%2820%2Asin%2855.7711%29%29%29\".
\n" ); document.write( "16.5 meters.
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