document.write( "Question 868407: How many pounds of $1.20 per pound nut mixture must be mixed with two pounds of 90c per pound mixture to produce a mixture that sells for $1.00 per pound? \n" ); document.write( "

Algebra.Com's Answer #523530 by josgarithmetic(39620) $\"\"$ $\"About$

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Yes, this is a mixture problem and the concentration unit is dollars per pound.\r
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\n" ); document.write( "\n" ); document.write( "Let h = the pounds of the higher priced nuts to add.\r
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\n" ); document.write( "\n" ); document.write( "Accounting for poundage: h+2,... we do not know what its value is but we can use the expression.\r
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\n" ); document.write( "\n" ); document.write( "Accounting for money: $\"highlight_green%28%281.2%29h%2B%280.9%29%2A2=%281.0%29%28h%2B2%29%29\"$ . The equation could also be first formed as its equivalent rational equation, but your first step might be to transform into this green-highlited form here. Notice that 90 cents is 0.90 dollars.\r
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\n" ); document.write( "\n" ); document.write( "The only variable is h. Solve for h. \n" ); document.write( "

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