document.write( "Question 868377: (3 + squareroot-4)(4 + squareroot-1)
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Algebra.Com's Answer #523510 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%283+%2B+sqrt%28-4%29%29%284+%2B+sqrt%28-1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283+%2B+sqrt%28-1%2A4%29%29%284+%2B+sqrt%28-1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283+%2B+sqrt%28-1%29%2Asqrt%284%29%29%284+%2B+sqrt%28-1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283+%2B+i%2A2%29%284+%2B+i%29\" By definition: \"i+=+sqrt%28-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283+%2B+2i%29%284+%2B+i%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%284+%2B+i%29%2B2i%284+%2B+i%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%284%29+%2B+3%28i%29%2B2i%284%29+%2B+2i%28i%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"12+%2B+3i+%2B+8i+%2B+2i%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"12+%2B+3i+%2B+8i+%2B+2%28-1%29\" Since \"i+=+sqrt%28-1%29\", squaring both sides gives \"i%5E2+=+-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"12+%2B+3i+%2B+8i+-+2\"\r
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\n" ); document.write( "\n" ); document.write( "\"10+%2B+11i\"\r
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\n" ); document.write( "\n" ); document.write( "Answer: \"%283+%2B+sqrt%28-4%29%29%284+%2B+sqrt%28-1%29%29=10+%2B+11i\"
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