document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=868363>Question 868363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One card is dealt from a standard 52-card deck of  cards .find each of the probabilities below:<BR>\n" );
document.write( "A.) let event E= {the card drawn is a club }<BR>\n" );
document.write( "Find P(E)\r<BR>\n" );
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document.write( "B.) let event F= {the card drawn is a red card that is greater than four and less than 9}<BR>\n" );
document.write( "Find P(F) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #523502 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=523502\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 13 clubs. This is out of 52 cards total\r<BR>\n" );
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document.write( "P(E) = 13/52 = <font color=\"red\">1/4</font>\r<BR>\n" );
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document.write( "These cards are between 4 and 9 (excluding both endpoints): 5, 6, 7, 8\r<BR>\n" );
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document.write( "There are 2 versions of each that are red (eg: 5 of hearts and 5 of diamonds)\r<BR>\n" );
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document.write( "So there are 4*2 = 8 cards total that are red and between 4 and 9 (excluding both endpoints). This is out of 52 cards total.\r<BR>\n" );
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document.write( "P(F) = 8/52 = <font color=\"red\">2/13</font> </SPAN>\n" );
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