document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=868334>Question 868334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following trigonometric equations such that 0<=x<=2pi\r<BR>\n" );
document.write( "\n" );
document.write( "&#8730;3=(tan x+tan(pi/3))/1-tan x tan(pi/3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #523484 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=523484\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the following trigonometric equations such that 0<=x<=2pi <BR>\n" );
document.write( "&#8730;3=(tan x+tan(pi/3))/1-tan x tan(pi/3)<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "tan(x+(pi/3)) = sqrt(3)<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "x+(pi/3) = sqrt(3)<BR>\n" );
document.write( "x = sqrt(3)-(pi/3)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "x = (3sqrt(3)-pi)/3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "x = 0.6849<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );