document.write( "Question 868329: Solve cos2x+sinx=1in[0,2pi)? \n" ); document.write( "
Algebra.Com's Answer #523481 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve cos(2x)+sinx=1in[0,2pi)? \n" ); document.write( "----- \n" ); document.write( "cos(2x) = cos^2(x)-sin^2(x) = 1-2sin^2(x) \n" ); document.write( "-------------------------- \n" ); document.write( "Your equation: \n" ); document.write( "1-2sin^2(x)+sin(x) = 1 \n" ); document.write( "----- \n" ); document.write( "Rearrange: \n" ); document.write( "2sin^2(x)-sin(x) = 0 \n" ); document.write( "---- \n" ); document.write( "Factor: \n" ); document.write( "sin(x)[2sin(x)-1] = 0 \n" ); document.write( "----- \n" ); document.write( "sin(x) = 0 or sin(x) = 1/2 \n" ); document.write( "------- \n" ); document.write( "x = 0 or pi or pi/6 or (5/6)pi \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------------- \n" ); document.write( "------ \n" ); document.write( " \n" ); document.write( " |