document.write( "Question 868329: Solve cos2x+sinx=1in[0,2pi)? \n" ); document.write( "
Algebra.Com's Answer #523481 by stanbon(75887)\"\" \"About 
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Solve cos(2x)+sinx=1in[0,2pi)?
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\n" ); document.write( "cos(2x) = cos^2(x)-sin^2(x) = 1-2sin^2(x)
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\n" ); document.write( "Your equation:
\n" ); document.write( "1-2sin^2(x)+sin(x) = 1
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\n" ); document.write( "Rearrange:
\n" ); document.write( "2sin^2(x)-sin(x) = 0
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\n" ); document.write( "Factor:
\n" ); document.write( "sin(x)[2sin(x)-1] = 0
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\n" ); document.write( "sin(x) = 0 or sin(x) = 1/2
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\n" ); document.write( "x = 0 or pi or pi/6 or (5/6)pi
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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