document.write( "Question 73087: radicalx-1=3 \n" ); document.write( "
Algebra.Com's Answer #52345 by rmromero(383)\"\" \"About 
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document.write( "          \"sqrt%28x-1%29+=+3\"\r
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document.write( "          \"%28sqrt%28x-1%29%29%5E2\" = \"3%5E2\"\r
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document.write( "                    x - 1 = 9
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document.write( "                        x = 9 + 1
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document.write( "                        x = 10\r
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document.write( "Checking:\r
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document.write( "  \"sqrt%28x-1%29+=+3\", x = 10\r
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document.write( "  \"sqrt%2810-1%29+=+3\"\r
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document.write( "  \"sqrt%289%29+=+3\"\r
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document.write( "         3 = 3 --------------> True\r
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document.write( "Therefore x = 10
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