document.write( "Question 868250: how do you solve the following?
\n" ); document.write( "log3x = log4 + log (x-1)\r
\n" ); document.write( "\n" ); document.write( "log of base 8 of x^2 = log of base 8 (3x+4)\r
\n" ); document.write( "\n" ); document.write( "What numbers do you use to fill in for the varriables?:
\n" ); document.write( "A=P{1+r/n}^nt\r
\n" ); document.write( "\n" ); document.write( "ex. Laura borrows $2500 at a rate of 10.5% compounded monthly. Find how much Laura owes at the end of 4 years.\r
\n" ); document.write( "\n" ); document.write( "I am studying for a quiz tomorrow and cannot get ahold of any classmates for help. Thanks.
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Algebra.Com's Answer #523433 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

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\n" ); document.write( "\"log%2810%2C+3x%2F4%28x-1%29%29+=+0\"
\n" ); document.write( " \"3x%2F4%28x-1%29+=+1\"
\n" ); document.write( " 3x = 4x-4
\n" ); document.write( " -x = -4, x = 4
\n" ); document.write( "A=P{1+r/n}^nt
\n" ); document.write( "A = Accumulated Amount
\n" ); document.write( "P= principal =
\n" ); document.write( "r= annual rate = .
\n" ); document.write( "n= periods per year =
\n" ); document.write( "t= years =
\n" ); document.write( "A = 2500(1+ .105/12)^48
\n" ); document.write( "A = 2500(1.00875)^48 = $3,797.96
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