document.write( "Question 867896: HELLO.....I am asked to solve 2(x+1)exponent 2/3 + 3(x+1)exponent 1/3=0 by u- substitution. Sorry I did not know how to type exponents up after the parenthesis. I tried 2u squared +3u +1=0. Came up with (2u+1)(u+1)=0 so far \n" ); document.write( "

Algebra.Com's Answer #523376 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Not sure what your \"u\" substitution was because
\n" ); document.write( " $\"%282u%2B1%29%28u%2B1%29=2u%5E2%2B3u%2B1\"$
\n" ); document.write( "but your equation is $\"2u%5E2%2B3u=0\"$ .
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( " $\"u=%28x%2B1%29%5E%281%2F3%29\"$
\n" ); document.write( " $\"u%5E2=%28x%2B1%29%5E%282%2F3%29\"$
\n" ); document.write( " $\"2u%5E2%2B3u=0\"$
\n" ); document.write( " $\"u%282u%2B3%29=0\"$
\n" ); document.write( "By the zero product property, you have two \"u\" solutions,
\n" ); document.write( " $\"u=0\"$
\n" ); document.write( " $\"%28x%2B1%29%5E%281%2F3%29=0\"$
\n" ); document.write( " $\"x%2B1=0\"$
\n" ); document.write( " $\"x=-1\"$
\n" ); document.write( "and
\n" ); document.write( " $\"2u%2B3=0\"$
\n" ); document.write( " $\"2u=-3\"$
\n" ); document.write( " $\"u=-3%2F2\"$
\n" ); document.write( " $\"%28x%2B1%29%5E%281%2F3%29=-3%2F2\"$
\n" ); document.write( "This is not a valid \"x\" solution.
\n" ); document.write( " \n" ); document.write( "

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