document.write( "Question 73031: What is the integer if twice the square of a positive integer is 35 more than 9 times that integer? how do I get the integer I am lost. \n" ); document.write( "
Algebra.Com's Answer #52334 by ankor@dixie-net.com(22740)\"\" \"About 
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What is the integer if twice the square of a positive integer is 35 more than 9 times that integer?
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\n" ); document.write( "Let x = the integer
\n" ); document.write( "Just write what it says:
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\n" ); document.write( "Twice x^2 = 35 more than than 9x
\n" ); document.write( "2x^2 = 9x + 35
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\n" ); document.write( "Arrange as a quadratic equation:
\n" ); document.write( "2x^2 - 9x - 35 = 0
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\n" ); document.write( "Factors to:
\n" ); document.write( "(2x + 5)(x - 7) = 0
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\n" ); document.write( "x = 7, it said the \"positive integer\"
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\n" ); document.write( "Check:
\n" ); document.write( "2(7^2) = 9(7) + 35
\n" ); document.write( "98 = 63 + 35
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