document.write( "Question 9540: how can I solve this expression help please :\r
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document.write( " 13- 3a for a = -1 \n" );
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Algebra.Com's Answer #5233 by thecampusnerd(13) ![]() You can put this solution on YOUR website! Alright, since a = -1, plug -1 in for \"a\". \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your equation will come out like this: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now use your Order of Operations. Notice that the 3 has a minus sign in front of it. Because of that very minus sign, we're going to call it -3. Using the Order of Ops, you'll mulitiply -3 by -1, which is positive 3 (A negative times a negative equals a positive. The negatives cancel each other out.)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Because the 3 is now positive, you're going to change the expression from 13 - 3 to 13 + 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do the math and you have your answer. 13 + 3 = 16.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, let's see it in the less wordy version...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |