document.write( "Question 9540: how can I solve this expression help please :\r
\n" ); document.write( "\n" ); document.write( " 13- 3a for a = -1
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Algebra.Com's Answer #5233 by thecampusnerd(13)\"\" \"About 
You can put this solution on YOUR website!
Alright, since a = -1, plug -1 in for \"a\". \r
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\n" ); document.write( "\n" ); document.write( "Your equation will come out like this: \"13-3%28-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now use your Order of Operations. Notice that the 3 has a minus sign in front of it. Because of that very minus sign, we're going to call it -3. Using the Order of Ops, you'll mulitiply -3 by -1, which is positive 3 (A negative times a negative equals a positive. The negatives cancel each other out.)\r
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\n" ); document.write( "\n" ); document.write( "Because the 3 is now positive, you're going to change the expression from 13 - 3 to 13 + 3.\r
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\n" ); document.write( "\n" ); document.write( "Do the math and you have your answer. 13 + 3 = 16.\r
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\n" ); document.write( "\n" ); document.write( "Now, let's see it in the less wordy version...\r
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\n" ); document.write( "\n" ); document.write( "\"13-3a\"\r
\n" ); document.write( "\n" ); document.write( "\"13-3%28-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"13%2B3=16\"
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