document.write( "Question 867964: the jones family invests $11000 in two different money market accounts. one account pays 7% interest, and the other pays 8.5%. by the end of year the Jones family receives $860 in interest. How much did they invest in each account? \n" ); document.write( "
Algebra.Com's Answer #523299 by mananth(16949) You can put this solution on YOUR website! Part I 7.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 8.50% per annum ------------ Amount invested = y \n" ); document.write( " 11000 \n" ); document.write( "Interest----- 860.00 \n" ); document.write( " \n" ); document.write( "Part I 7.00% per annum ---x \n" ); document.write( "Part II 8.50% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 11000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "7.00% x + 8.50% y= 860 \n" ); document.write( "Multiply by 100 \n" ); document.write( "7 x + 8.5 y= 86000.00 --------2 \n" ); document.write( "Multiply (1) by -7 \n" ); document.write( "we get \n" ); document.write( "-7 x -7 y= -77000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 1.5 y= 9000 \n" ); document.write( "divide by 1.5 \n" ); document.write( " y = 6000 \n" ); document.write( "Part I 7.00% $ 5000 \n" ); document.write( "Part II 8.50% $ 6000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "5000 --------- 7.00% ------- 350.00 \n" ); document.write( "6000 ------------- 8.50% ------- 510.00 \n" ); document.write( "Total -------------------- 860.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |