document.write( "Question 867911: Identify the vertex, axis of symmetry, and intercepts for the graph of the function. x=y^2+6y-1 (use completing the square method) (then graph). \n" ); document.write( "
Algebra.Com's Answer #523261 by lwsshak3(11628)\"\" \"About 
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Identify the vertex, axis of symmetry, and intercepts for the graph of the function. x=y^2+6y-1 (use completing the square method) (then graph).
\n" ); document.write( "***
\n" ); document.write( "x=y^2+6y-1
\n" ); document.write( "x=(y^2+6y+9)-9-1
\n" ); document.write( "x=(y+3)^2-10
\n" ); document.write( "(y+3)^2=x+10
\n" ); document.write( "This is an equation of a parabola that opens right
\n" ); document.write( "vertex:(-10,-3)
\n" ); document.write( "axis of symmetry:y=3
\n" ); document.write( "..
\n" ); document.write( "x-intercepts:
\n" ); document.write( "set y=0
\n" ); document.write( "x=y^2+6y-1
\n" ); document.write( "x=-1
\n" ); document.write( "..
\n" ); document.write( "y-intercepts
\n" ); document.write( "set x=0
\n" ); document.write( "(y+3)^2=x+10
\n" ); document.write( "y+3=±√10
\n" ); document.write( "y=-3±√10
\n" ); document.write( "y≈-6.16
\n" ); document.write( "or
\n" ); document.write( "y≈0.16
\n" ); document.write( "..
\n" ); document.write( "see graph below:
\n" ); document.write( "y=±(x+10)^.5-3
\n" ); document.write( " \n" ); document.write( "
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