document.write( "Question 867851: A certain radioactive substance decays according to the formula q(t)= q0e^-.0063t. where q0 is the initial amount of the substance and t is the time in days. Approximate the half-life of the substance. \n" ); document.write( "
Algebra.Com's Answer #523230 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A certain radioactive substance decays according to the formula q(t)= q0e^-.0063t. where q0 is the initial amount of the substance and t is the time in days. Approximate the half-life of the substance. \n" ); document.write( ": \n" ); document.write( "let Qo = 1, then Q(t) = .5 \n" ); document.write( "A simple equation \n" ); document.write( " \n" ); document.write( "find the ln of both sides \n" ); document.write( " \n" ); document.write( "the log equiv of exponents \n" ); document.write( "-.0063t*ln(e) = ln(.5) \n" ); document.write( "the ln of e is one so we have \n" ); document.write( "-.0063t = -.693147 \n" ); document.write( "t = \n" ); document.write( "t = +110 days is the half life of the substance \n" ); document.write( " |