document.write( "Question 867851: A certain radioactive substance decays according to the formula q(t)= q0e^-.0063t. where q0 is the initial amount of the substance and t is the time in days. Approximate the half-life of the substance. \n" ); document.write( "
Algebra.Com's Answer #523230 by ankor@dixie-net.com(22740)\"\" \"About 
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A certain radioactive substance decays according to the formula q(t)= q0e^-.0063t. where q0 is the initial amount of the substance and t is the time in days. Approximate the half-life of the substance.
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\n" ); document.write( "let Qo = 1, then Q(t) = .5
\n" ); document.write( "A simple equation
\n" ); document.write( "\"1%2Ae%5E%28-.0063t%29+=+.5\"
\n" ); document.write( "find the ln of both sides
\n" ); document.write( "\"ln%28e%5E%28-.0063t%29%29+=+ln%28.5%29\"
\n" ); document.write( "the log equiv of exponents
\n" ); document.write( "-.0063t*ln(e) = ln(.5)
\n" ); document.write( "the ln of e is one so we have
\n" ); document.write( "-.0063t = -.693147
\n" ); document.write( "t = \"%28-.693147%29%2F%28-.0063%29\"
\n" ); document.write( "t = +110 days is the half life of the substance
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