document.write( "Question 867784: You need 715 mL of a 50% alcohol solution. On hand, you have a 40% alcohol mixture and a 95% alcohol mixture. How much of each mixture will you need to obtain the desired solution?\r
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document.write( "You will need
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document.write( " mL of the 40% solution
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document.write( "and
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document.write( " mL of the 95% solution. \n" );
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Algebra.Com's Answer #523180 by Alan3354(69443) You can put this solution on YOUR website! Do it like this one. Only the numbers are different. \n" ); document.write( "----------- \n" ); document.write( "Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use? \n" ); document.write( "================ \n" ); document.write( "e = amount of 8% \n" ); document.write( "f = amount of 56% \n" ); document.write( "--- \n" ); document.write( "e+ f = 8 (total solution) \n" ); document.write( "8e + 56f = 20*8 (total saline) \n" ); document.write( "--- \n" ); document.write( "e+ f = 8 \n" ); document.write( "e + 7f = 20 \n" ); document.write( "------------ Subtract \n" ); document.write( "-6f = -12 \n" ); document.write( "f = 2 \n" ); document.write( "e = 6 \n" ); document.write( " |