document.write( "Question 867606: Determine k such that the solutions of $\"9x%5E2+%2B+9x+=+k\"$ are complex numbers. \n" ); document.write( "

Algebra.Com's Answer #523109 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
Same as $\"9x%5E2%2B9x-k=0\"$ .\r
\n" ); document.write( "\n" ); document.write( "Wanting solutions complex, this is a discriminant problem exercise.
\n" ); document.write( "Discriminant is $\"9%5E2-4%2A9%2A%28-k%29\"$ .
\n" ); document.write( " $\"9%5E2-4%2A9%2A%28-k%29%3C0\"$
\n" ); document.write( " $\"81%2B36k%3C0\"$
\n" ); document.write( " $\"36k%3C-81\"$
\n" ); document.write( " $\"k%3C-81%2F36\"$
\n" ); document.write( " $\"highlight%28k%3C-2%261%2F4%29\"$ \n" ); document.write( "

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