document.write( "Question 73047: How many liters of a 20% alcohol solution and a 10% alcohol solution should be mixed to obtain 50 liters of a 12% alcohol solution? \n" ); document.write( "

Algebra.Com's Answer #52308 by jim_thompson5910(35256) $\"\"$ $\"About$

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Let x=number of liters of 20% solution, y=# of liters of 10% solution
\n" ); document.write( "If we want 50 liters of the combined sum of the 2 solutions it will look like this
\n" ); document.write( " $\"x%2By=50\"$
\n" ); document.write( "Since we want 50 liters of 12% solution it comes to
\n" ); document.write( " $\"50%2A0.12=6\"$
\n" ); document.write( "And to mix the solutions we use the equation (for instance 30% of 10 liters + 20% of 10 liters = 5 liters, this is an example not the answer)
\n" ); document.write( " $\"0.2x%2B0.1y=6\"$
\n" ); document.write( "Now use the linear solver to get our answer
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Solved by pluggable solver: Linear System solver (using determinant)

Solve:
\n" ); document.write( " $\"+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+50%2C%0D%0A++++0.2%5Cx+%2B+0.1%5Cy+=+6+%29%0D%0A++\"$
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\n" ); document.write( " Any system of equations:
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\n" ); document.write( " has solution
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\n" ); document.write( " or
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\n" ); document.write( " (x=10, y=40}
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\n" ); document.write( "\n" ); document.write( "So we want 10 liters of 20% solution and 40 liters of 10% solution \n" ); document.write( "

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