document.write( "Question 867565: Convert the rectangular equation to polar form. (Use r and use theta for θ as necessary.)
\n" ); document.write( "x2 + y2 = 18
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Algebra.Com's Answer #523079 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%2By%5E2=18\", which is really \"%28x-0%29%5E2%2B%28y-0%29%5E2=%28sqrt%2818%29%29%5E2\" is in the form \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" which is a circle with center (h,k) = (0,0) and radius \"r%5E2=18\" ---> \"r+=+sqrt%2818%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now simplify \"r+=+sqrt%2818%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+sqrt%2818%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+sqrt%289%2A2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+sqrt%289%29%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+3%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "So the answer, as simplified as possible, is \"r+=+3%2Asqrt%282%29\". This is because this is simply a circle with radius \"3%2Asqrt%282%29\" and when you have something like \"r+=+2\", you mean \"a circle with center (0,0) with radius 2\"
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