document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=867517>Question 867517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a child is given cards with A, C, D, G, O, and T on them, what is the probability he or she could spell GOT by guessing the correct arrangement of 3 cards from the 6? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #523070 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=523070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the probability will be 1 / 6P3 which is equal to 1/120.\r<BR>\n" );
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document.write( "there are 6P3 possible number of ordered arrangement of sets of 3 cards taken from 6.\r<BR>\n" );
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document.write( "6P3 is the formula for the permutation of 6 things taken 3 at a time.  \r<BR>\n" );
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document.write( "that equals 6! / 3! which is equal to 6*5*4 which is equal to 120.\r<BR>\n" );
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document.write( "a permutation is an ordered arrangement.\r<BR>\n" );
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document.write( "the general formula for a permutation of n things taken x at a time is:\r<BR>\n" );
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document.write( "nPx = n! / (n-x)!\r<BR>\n" );
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document.write( "when n = 6 and x = 3, this becomes 6P3 = 6! / (6-3)! which becomes 6! / 3!.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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