document.write( "Question 867524: suppose a random sample of 1750 households with television showed that 69.5 percent of them have cable television. Is this sufficient evidence, at the 0.05 significance level, to claim more than two-thirds of all television households have cable televisions? \n" ); document.write( "
Algebra.Com's Answer #523064 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! suppose a random sample of 1750 households with television showed that 69.5 percent of them have cable television. Is this sufficient evidence, at the 0.05 significance level, to claim more than two-thirds of all television households have cable televisions? \n" ); document.write( "------------------------------- \n" ); document.write( "Ho: p <= 2/3 \n" ); document.write( "Ha: p > 2/3 (claim) \n" ); document.write( "--------------------------------- \n" ); document.write( "p-hat = 0.695 \n" ); document.write( "---- \n" ); document.write( "z(0.695) = (0.695-(2/3))/sqrt[(2/3)(1/3)/1750] = 2.5143 \n" ); document.write( "----------------------------- \n" ); document.write( "p-value = P(z > 2.5143) = normalcdf(2.5143,100) = 0.006 \n" ); document.write( "--------------------------------- \n" ); document.write( "Conclusion: Since the p-value is less than 5%, reject Ho. \n" ); document.write( "The test results support the claim. \n" ); document.write( "---------------------------------------- \n" ); document.write( " |