document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=866073>Question 866073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! I would like to know how to solve for x in this log problem.\r<BR>\n" );
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document.write( "log(2x+5) * log(9x^2) = 0\r<BR>\n" );
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document.write( "This problem should have 3 solutions: -2, -1/3, +1/3.\r<BR>\n" );
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document.write( "Please help me. Thank you! :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #523047 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=523047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2, -1/3, +1/3 are correct<BR>\n" );
document.write( "The key is log(1)=0<BR>\n" );
document.write( "log(2x+5)*log(9x^2) = 0<BR>\n" );
document.write( "log(9x^2) = 0<BR>\n" );
document.write( "x^2=1/9<BR>\n" );
document.write( "x=-1/3 <BR>\n" );
document.write( "x=+1/3<BR>\n" );
document.write( "log(2x+5)=0<BR>\n" );
document.write( "2x+5=1<BR>\n" );
document.write( "2x=-4<BR>\n" );
document.write( "x=-2\r<BR>\n" );
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document.write( " </SPAN>\n" );
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