document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=867503>Question 867503</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi there, I have a question pertaining to solving exponential equations with common bases. I understand the whole when bases are equal the exponents must be equal, but I don't quite get how to solve so the exponents are equal. <BR>\n" );
document.write( "For example<BR>\n" );
document.write( "3^2x+6 = 3^-3 <BR>\n" );
document.write( "They have the same bases so all I've got to do is solve:<BR>\n" );
document.write( "2x+6 = -3<BR>\n" );
document.write( "And it becomes 2X = -9. I don't understand how you get 2x = -9, <BR>\n" );
document.write( ", and then x = -9/2.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #523043 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=523043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> another way<BR>\n" );
document.write( "3^(2x+6) = 3^-3<BR>\n" );
document.write( "3^(2(x+3)) = 3^-3<BR>\n" );
document.write( "2(x+3)=-3<BR>\n" );
document.write( "x+3=-3/2<BR>\n" );
document.write( "x=-3/2-3<BR>\n" );
document.write( "x=-9/2\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );