document.write( "Question 867410: 1)Prove that if a+a=a a=0 a is an element of ring R\r
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document.write( "2) if every element of a ring R is an idempotent , prove that a+a=0 3) what is addition and multiplication table for {0,1,x,1+x} note that each element is an idempotent .
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Algebra.Com's Answer #523037 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! 1)The properties of a Ring include that it is a Group under addition whose identity is 0 and inverse notation is -r where r is member of the Group. \n" ); document.write( "In a Group under addition every element (a) has an inverse such that \n" ); document.write( "a + b = b + a = 0 and b is a's inverse denoted by -a \n" ); document.write( "we are given a + a = 0, a = 0 which implies that a is its own inverse \n" ); document.write( "note that 0, the additive identity element is unique and a required member of the additive Group, under closure property a + a is a member of the additive Group \n" ); document.write( "2)An idempotent element a of the Ring is defined as \n" ); document.write( "a^2 = a^1, thus the element is idempotent under the Ring's multiplication and moreover we can say a^1 = a^2 = a^3 = a^4 = .....a^n or any positive integer n \n" ); document.write( "if every element of a ring R is an idempotent, we are dealing with a Boolean Ring \n" ); document.write( "a+a = (a+a)^2 = a^2 + a^2 +a^2 +a^2 = a +a +a +a \n" ); document.write( "now subtract a+a from both sides of the = \n" ); document.write( "0 = a +a \n" ); document.write( "addition table \n" ); document.write( "row/ 0 1 x 1+x \n" ); document.write( "column \n" ); document.write( "0 0 1 x 1\r \n" ); document.write( "\n" ); document.write( "1 1 0 1+x x\r \n" ); document.write( "\n" ); document.write( "x x 1+x 0 1\r \n" ); document.write( "\n" ); document.write( "1+x 1+x x 1 0 \n" ); document.write( "multiplication table \n" ); document.write( "row/ 0 1 x 1+x \n" ); document.write( "column \n" ); document.write( "0 0 0 0 0 \r \n" ); document.write( "\n" ); document.write( "1 0 1 x 1+x\r \n" ); document.write( "\n" ); document.write( "x 0 x x 0\r \n" ); document.write( "\n" ); document.write( "1+x 0 x 0 1+x\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |