document.write( "Question 867322: 3. A ball is dropped vertically from a height of 50 meters. After each bounce, the ball reaches a maximum height equal to 80 percent of the maximum height of the previous bounce.
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document.write( "a.) Write the first three terms of the sequence. Explain how you know what they are.
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document.write( "b.) Find the height to the nearest tenth of a meter of the ball after the tenth bounce. Show and explain your work. \n" );
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Algebra.Com's Answer #522959 by mananth(16946)![]() ![]() You can put this solution on YOUR website! drops from 50 m \n" ); document.write( "height reached = 0.8 time previous height\r \n" ); document.write( "\n" ); document.write( "h2= 0.8*50 = 40\r \n" ); document.write( "\n" ); document.write( "h3=0.8*40=32\r \n" ); document.write( "\n" ); document.write( "The first three terms are 50, 40, 32\r \n" ); document.write( "\n" ); document.write( "t2/t1= 50/40 = 5/4\r \n" ); document.write( "\n" ); document.write( "t3/t2= 40/32 = 5/4\r \n" ); document.write( "\n" ); document.write( "The ratio of the term and the preceeding term is a constant. The common ratio. and less than 1\r \n" ); document.write( "\n" ); document.write( "It is a geometric sequence\r \n" ); document.write( "\n" ); document.write( "after 10 bounces\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tn=a*r^(n-1) \n" ); document.write( "nth. term of a GP\r \n" ); document.write( "\n" ); document.write( "a=50 \n" ); document.write( "r=0.8 \n" ); document.write( "n=10\r \n" ); document.write( "\n" ); document.write( "t10 = 50*0.8^9 \n" ); document.write( "=6.71 m \n" ); document.write( " |