document.write( "Question 867346: Can someone solve this word problem for me? \r
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document.write( "find three consecutive positive odd integers such that the sum of the squares of the first and second integers is equal to the square of the third integer plus 9 \n" );
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Algebra.Com's Answer #522945 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the odd integers be x, x+2,x+4\r \n" ); document.write( "\n" ); document.write( "sum of squares of first two \n" ); document.write( "x^2+(x+2)^2\r \n" ); document.write( "\n" ); document.write( "which is equal to\r \n" ); document.write( "\n" ); document.write( "(x+4)^2+9\r \n" ); document.write( "\n" ); document.write( "x^2+(x+2)^2=(x+4)^2+9\r \n" ); document.write( "\n" ); document.write( "x^2+x^2+4x+4=x^2+8x+16+9\r \n" ); document.write( "\n" ); document.write( "2x^2+4x+4=x^2+8x+25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2-4x-21=0\r \n" ); document.write( "\n" ); document.write( "x^2-7x+4x-21=0\r \n" ); document.write( "\n" ); document.write( "x(x-7)+4(x-7)=0\r \n" ); document.write( "\n" ); document.write( "(x-7)(x+4)=0\r \n" ); document.write( "\n" ); document.write( "x=7 Or -4\r \n" ); document.write( "\n" ); document.write( "but the number is positive \n" ); document.write( "so the numbers are 7,9,11\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |