document.write( "Question 867342: Who am I?
\n" );
document.write( "I am a three digit number.
\n" );
document.write( "I am odd.
\n" );
document.write( "My ones digit is greater than my tens digit.
\n" );
document.write( "My hundreds digit is prime.
\n" );
document.write( "My tens digit is twice my hundreds digit.
\n" );
document.write( "Two of my digits are square numbers. \n" );
document.write( "
Algebra.Com's Answer #522937 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! Suppose the 3-digit number is abc.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a is prime, and two digits are squares --> b, c are squares (in particular, c = 9 or c = 1).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If c = 1, then b = 0 (since c > b), but this implies a = 0, which doesn't work.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If c = 9, then b = 4 or 1. b cannot be 1 since b = 2a, so b = 4, and a = 2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "# = 249 \n" ); document.write( " |