document.write( "Question 867254: Solve
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document.write( "a)log(base 2)(x+1) + log(base 2)(x-1) = 3
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document.write( "b)log(base 2)(x+2) = 2 - log(base 2)(x-1)\r
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document.write( "Can you please help me out? Thanks so much in advance:)\r
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Algebra.Com's Answer #522936 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve \n" ); document.write( "a) \n" ); document.write( "addition of logs, is multiply \n" ); document.write( " \n" ); document.write( "FOIL \n" ); document.write( " \n" ); document.write( "Write exponent equiv of logs \n" ); document.write( "x^2 -1 = \n" ); document.write( "x^2 - 1 = 8 \n" ); document.write( "x^2 - 1 - 8 = 0 \n" ); document.write( "x^2 - 9 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x-3)(x+3) = 0 \n" ); document.write( "x = +3, is the only solution (no negative allowed in a log) \n" ); document.write( ": \n" ); document.write( "b) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The exponent equiv \n" ); document.write( "x^2 + x - 2 = \n" ); document.write( "x^2 + x - 2 = 4 \n" ); document.write( "x^2 + x - 2 - 4 = 0 \n" ); document.write( "x^2 + x - 6 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x+3)(x-2) = 0 \n" ); document.write( "x = 2, the positive solution all we want here \n" ); document.write( " |