document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=867331>Question 867331</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tom and Leo jogged together for about 1 hr at the speed of 5mph. After that, Tom jogged faster by 1 mph and Leo jogged slower by 1mph. How long will it take them to be 1 mile apart, after they started jogged at different speed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #522932 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=522932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tom and Leo jogged together for about 1 hr at the speed of 5mph. After that, Tom jogged faster by 1 mph and Leo jogged slower by 1mph. How long will it take them to be 1 mile apart, after they started jogged at different speed?<BR>\n" );
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document.write( "let x=time it will take for Leo and Tom to be 1-mile apart<BR>\n" );
document.write( "4= Leo's speed<BR>\n" );
document.write( "6= Tom's speed<BR>\n" );
document.write( "travel time*speed=distance<BR>\n" );
document.write( "6x-4x=1<BR>\n" );
document.write( "2x=1<BR>\n" );
document.write( "x=1/2<BR>\n" );
document.write( "time it will take for Leo and Tom to be 1-mile apart=1/2 hr<BR>\n" );
document.write( " </SPAN>\n" );
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